私はAndroidアプリ開発に不慣れです、必要なのは2つのテキストボックスのユーザー名とパスワードを持っていることです。サーバーに投稿し、phpページを使用してDBで確認します。ログインが成功した場合次の画面に移動します。それ以外の場合は、ログインエラーを示すメッセージボックスを表示します。どうすればよいですか?
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://google.com");
EditText tw =(EditText) findViewById(R.id.EditText01);
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
int status = response.getStatusLine().getStatusCode();
tw.setText(status);
} catch (ClientProtocolException e) {
tw.setText(e.toString());
} catch (IOException e) {
tw.setText(e.toString());
}
}
このクラスを使用します。
import Java.io.BufferedReader;
import Java.io.IOException;
import Java.io.InputStreamReader;
import Java.io.OutputStreamWriter;
import Java.net.HttpURLConnection;
import Java.net.URL;
import Android.app.Activity;
import Android.os.Bundle;
import Android.view.View;
import Android.view.View.OnClickListener;
import Android.widget.Button;
import Android.widget.EditText;
import Android.widget.Toast;
public class HttpLogin extends Activity {
/** Called when the activity is first created. */
private Button login;
private EditText username, password;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
login = (Button) findViewById(R.id.login);
username = (EditText) findViewById(R.id.username);
password = (EditText) findViewById(R.id.password);
login.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
String mUsername = username.getText().toString();
String mPassword = password.getText().toString();
tryLogin(mUsername, mPassword);
}
});
}
protected void tryLogin(String mUsername, String mPassword)
{
HttpURLConnection connection;
OutputStreamWriter request = null;
URL url = null;
String response = null;
String parameters = "username="+mUsername+"&password="+mPassword;
try
{
url = new URL("your login URL");
connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestMethod("POST");
request = new OutputStreamWriter(connection.getOutputStream());
request.write(parameters);
request.flush();
request.close();
String line = "";
InputStreamReader isr = new InputStreamReader(connection.getInputStream());
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
// Response from server after login process will be stored in response variable.
response = sb.toString();
// You can perform UI operations here
Toast.makeText(this,"Message from Server: \n"+ response, 0).show();
isr.close();
reader.close();
}
catch(IOException e)
{
// Error
}
}
}
main.xmlは次のようになります。
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:Android="http://schemas.Android.com/apk/res/Android"
Android:orientation="vertical"
Android:layout_width="fill_parent"
Android:layout_height="fill_parent"
>
<EditText Android:hint="Username" Android:id="@+id/username" Android:layout_width="fill_parent" Android:layout_height="wrap_content"></EditText>
<EditText Android:hint="Password" Android:id="@+id/password" Android:layout_width="fill_parent" Android:layout_height="wrap_content" Android:inputType="textPassword"></EditText>
<Button Android:text="Sign In" Android:id="@+id/login" Android:layout_width="fill_parent" Android:layout_height="wrap_content"></Button>
</LinearLayout>
HttpClientを使用してPOSTリクエストを作成できます。例を参照してください ここ 。