配列Excel VBAの要素のインデックスを返す
整数のリストであるprLst配列があります。整数は、配列内の位置がスプレッドシートの特定の列を表すため、ソートされません。配列内の特定の整数を見つけ、そのインデックスを返す方法を知りたいです。
ワークシート上の配列を範囲に変えずにどのように表示するかについてのリソースはないようです。これは少し複雑に思えます。これはVBAでは不可能ですか？
Dim pos, arr, val
arr=Array(1,2,4,5)
val = 4
pos=Application.Match(val, arr, False)
if not iserror(pos) then
Msgbox val & " is at position " & pos
else
Msgbox val & " not found!"
end if
Match（.Indexを使用）を使用して2次元配列の次元の値を検索することを示すように更新されました。
Dim arr(1 To 10, 1 To 2)
Dim x
For x = 1 To 10
arr(x, 1) = x
arr(x, 2) = 11 - x
Next x
Debug.Print Application.Match(3, Application.Index(arr, 0, 1), 0)
Debug.Print Application.Match(3, Application.Index(arr, 0, 2), 0)
編集：コメントで@ARichが指摘したことをここで説明する価値があります-Index()を使用して配列をスライスすると、ループで実行している場合はひどいパフォーマンスになります。
テスト（以下のコード）では、Index（）アプローチはネストされたループを使用するよりもほぼ2000倍遅いです。
Sub PerfTest()
Const VAL_TO_FIND As String = "R1800:C8"
Dim a(1 To 2000, 1 To 10)
Dim r As Long, c As Long, t
For r = 1 To 2000
For c = 1 To 10
a(r, c) = "R" & r & ":C" & c
Next c
Next r
t = Timer
Debug.Print FindLoop(a, VAL_TO_FIND), Timer - t
' >> 0.00781 sec
t = Timer
Debug.Print FindIndex(a, VAL_TO_FIND), Timer - t
' >> 14.18 sec
End Sub
Function FindLoop(arr, val) As Boolean
Dim r As Long, c As Long
For r = 1 To UBound(arr, 1)
For c = 1 To UBound(arr, 2)
If arr(r, c) = val Then
FindLoop = True
Exit Function
End If
Next c
Next r
End Function
Function FindIndex(arr, val)
Dim r As Long
For r = 1 To UBound(arr, 1)
If Not IsError(Application.Match(val, Application.Index(arr, r, 0), 0)) Then
FindIndex = True
Exit Function
End If
Next r
End Function
バリアントの配列：
Public Function GetIndex(ByRef iaList() As Variant, ByVal value As Variant) As Long
Dim i As Long
For i = LBound(iaList) To UBound(iaList)
If value = iaList(i) Then
GetIndex = i
Exit For
End If
Next i
End Function
整数の最速バージョン（以下のprefテスト済み）
Public Function GetIndex(ByRef iaList() As Integer, ByVal value As Integer) As Integer
Dim i As Integer
For i = LBound(iaList) To UBound(iaList)
If iaList(i) = value Then: GetIndex = i: Exit For:
Next i
End Function
' a snippet, replace myList and myValue to your varible names: (also have not tested)
スニペットで、引数として参照渡しすることは何かを意味するという仮定をテストできます。 （答えはノーです）それを使用するには、myListとmyValueを変数名に置き換えます：
Dim found As Integer, foundi As Integer ' put only once
found = -1
For foundi = LBound(myList) To UBound(myList):
If myList(foundi) = myValue Then
found = foundi: Exit For
End If
Next
result = found
私がいくつかのベンチマークを作成したポイントを証明するために
結果は次のとおりです。
---------------------------
Milliseconds
---------------------------
result0: 5 ' just empty loop
result1: 2702 ' function variant array
result2: 1498 ' function integer array
result3: 2511 ' snippet variant array
result4: 1508 ' snippet integer array
result5: 58493 ' Excel function Application.Match on variant array
result6: 136128 ' Excel function Application.Match on integer array
---------------------------
OK
---------------------------
モジュール：
Public Declare Function GetTickCount Lib "kernel32.dll" () As Long
#If VBA7 Then
Public Declare PtrSafe Sub Sleep Lib "kernel32" (ByVal dwMilliseconds As LongPtr) 'For 64 Bit Systems
#Else
Public Declare Sub Sleep Lib "kernel32" (ByVal dwMilliseconds As Long) 'For 32 Bit Systems
#End If
Public Function GetIndex1(ByRef iaList() As Variant, ByVal value As Variant) As Long
Dim i As Long
For i = LBound(iaList) To UBound(iaList)
If value = iaList(i) Then
GetIndex = i
Exit For
End If
Next i
End Function
'maybe a faster variant for integers
Public Function GetIndex2(ByRef iaList() As Integer, ByVal value As Integer) As Integer
Dim i As Integer
For i = LBound(iaList) To UBound(iaList)
If iaList(i) = value Then: GetIndex = i: Exit For:
Next i
End Function
' a snippet, replace myList and myValue to your varible names: (also have not tested)
Public Sub test1()
Dim i As Integer
For i = LBound(iaList) To UBound(iaList)
If iaList(i) = value Then: GetIndex = i: Exit For:
Next i
End Sub
Sub testTimer()
Dim myList(500) As Variant, myValue As Variant
Dim myList2(500) As Integer, myValue2 As Integer
Dim n
For n = 1 To 500
myList(n) = n
Next
For n = 1 To 500
myList2(n) = n
Next
myValue = 100
myValue2 = 100
Dim oPM
Set oPM = New PerformanceMonitor
Dim result0 As Long
Dim result1 As Long
Dim result2 As Long
Dim result3 As Long
Dim result4 As Long
Dim result5 As Long
Dim result6 As Long
Dim t As Long
Dim a As Long
a = 0
Dim i
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
Next
result0 = oPM.TimeElapsed() ' GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = GetIndex1(myList, myValue)
Next
result1 = oPM.TimeElapsed()
'result1 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = GetIndex2(myList2, myValue2)
Next
result2 = oPM.TimeElapsed()
'result2 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
Dim found As Integer, foundi As Integer ' put only once
For i = 1 To 1000000
found = -1
For foundi = LBound(myList) To UBound(myList):
If myList(foundi) = myValue Then
found = foundi: Exit For
End If
Next
a = found
Next
result3 = oPM.TimeElapsed()
'result3 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
found = -1
For foundi = LBound(myList2) To UBound(myList2):
If myList2(foundi) = myValue2 Then
found = foundi: Exit For
End If
Next
a = found
Next
result4 = oPM.TimeElapsed()
'result4 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = pos = Application.Match(myValue, myList, False)
Next
result5 = oPM.TimeElapsed()
'result5 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = pos = Application.Match(myValue2, myList2, False)
Next
result6 = oPM.TimeElapsed()
'result6 = GetTickCount - t
MsgBox "result0: " & result0 & vbCrLf & "result1: " & result1 & vbCrLf & "result2: " & result2 & vbCrLf & "result3: " & result3 & vbCrLf & "result4: " & result4 & vbCrLf & "result5: " & result5 & vbCrLf & "result6: " & result6, , "Milliseconds"
End Sub
performanceMonitorという名前のクラス
Option Explicit
Private Type LARGE_INTEGER
lowpart As Long
highpart As Long
End Type
Private Declare Function QueryPerformanceCounter Lib "kernel32" (lpPerformanceCount As LARGE_INTEGER) As Long
Private Declare Function QueryPerformanceFrequency Lib "kernel32" (lpFrequency As LARGE_INTEGER) As Long
Private m_CounterStart As LARGE_INTEGER
Private m_CounterEnd As LARGE_INTEGER
Private m_crFrequency As Double
Private Const TWO_32 = 4294967296# ' = 256# * 256# * 256# * 256#
Private Function LI2Double(LI As LARGE_INTEGER) As Double
Dim Low As Double
Low = LI.lowpart
If Low < 0 Then
Low = Low + TWO_32
End If
LI2Double = LI.highpart * TWO_32 + Low
End Function
Private Sub Class_Initialize()
Dim PerfFrequency As LARGE_INTEGER
QueryPerformanceFrequency PerfFrequency
m_crFrequency = LI2Double(PerfFrequency)
End Sub
Public Sub StartCounter()
QueryPerformanceCounter m_CounterStart
End Sub
Property Get TimeElapsed() As Double
Dim crStart As Double
Dim crStop As Double
QueryPerformanceCounter m_CounterEnd
crStart = LI2Double(m_CounterStart)
crStop = LI2Double(m_CounterEnd)
TimeElapsed = 1000# * (crStop - crStart) / m_crFrequency
End Property
別の方法を次に示します。
Option Explicit
' Just a little test stub.
Sub Tester()
Dim pList(500) As Integer
Dim i As Integer
For i = 0 To UBound(pList)
pList(i) = 500 - i
Next i
MsgBox "Value 18 is at array position " & FindInArray(pList, 18) & "."
MsgBox "Value 217 is at array position " & FindInArray(pList, 217) & "."
MsgBox "Value 1001 is at array position " & FindInArray(pList, 1001) & "."
End Sub
Function FindInArray(pList() As Integer, value As Integer)
Dim i As Integer
Dim FoundValueLocation As Integer
FoundValueLocation = -1
For i = 0 To UBound(pList)
If pList(i) = value Then
FoundValueLocation = i
Exit For
End If
Next i
FindInArray = FoundValueLocation
End Function
'To return the position of an element within any-dimension array
'Returns 0 if the element is not in the array, and -1 if there is an error
Public Function posInArray(ByVal itemSearched As Variant, ByVal aArray As Variant) As Long
Dim pos As Long, item As Variant
posInArray = -1
If IsArray(aArray) Then
If not IsEmpty(aArray) Then
pos = 1
For Each item In aArray
If itemSearched = item Then
posInArray = pos
Exit Function
End If
pos = pos + 1
Next item
posInArray = 0
End If
End If
End Function
私がこれを行うことができる唯一の（面倒ではあるが便利で/比較的速い）方法は、任意の次元の配列を連結し、「/ [列番号] //\|」で1次元に減らすことです区切り文字として。
＆この1次元の列で単一セル結果の複数lookupallマクロ関数を使用します。
＆その後、インデックスマッチを使用して位置を引き出します。 （複数の検索一致を使用）
そうすることで、元の任意の次元の配列で、探している要素/文字列のすべての一致する出現とその位置を取得します。 1つのセル内。
このプロセス全体のマクロ/関数を書くことができればいいのに。それは私をもっと大騒ぎから救うでしょう。
これはあなたが探しているものですか？
public function GetIndex(byref iaList() as integer, byval iInteger as integer) as integer
dim i as integer
for i=lbound(ialist) to ubound(ialist)
if iInteger=ialist(i) then
GetIndex=i
exit for
end if
next i
end function
配列が0から始まるか1から始まるかを注意してください。また、位置0または1が関数によって返される場合、同じ関数が関数によって返されるTrueまたはFalseと混同されないようにしてください。
Function array_return_index(arr As Variant, val As Variant, Optional array_start_at_zero As Boolean = True) As Variant
Dim pos
pos = Application.Match(val, arr, False)
If Not IsError(pos) Then
If array_start_at_zero = True Then
pos = pos - 1
'initializing array at 0
End If
array_return_index = pos
Else
array_return_index = False
End If
End Function
Sub array_return_index_test()
Dim pos, arr, val
arr = Array(1, 2, 4, 5)
val = 1
'When array starts at zero
pos = array_return_index(arr, val)
If IsNumeric(pos) Then
MsgBox "Array starting at 0; Value found at : " & pos
Else
MsgBox "Not found"
End If
'When array starts at one
pos = array_return_index(arr, val, False)
If IsNumeric(pos) Then
MsgBox "Array starting at 1; Value found at : " & pos
Else
MsgBox "Not found"
End If
End Sub