Stack Overflowのレピュテーションの丸めと同じように、通貨でも同じことをしたいと思っています。
1,000ドル=> 1,000
$ 1,000,000 => 1m
JavaScript(できればjQuery)でこれを実現するにはどうすればよいですか?
これを行うための簡単な関数は次のとおりです。
function abbrNum(number, decPlaces) {
// 2 decimal places => 100, 3 => 1000, etc
decPlaces = Math.pow(10,decPlaces);
// Enumerate number abbreviations
var abbrev = [ "k", "m", "b", "t" ];
// Go through the array backwards, so we do the largest first
for (var i=abbrev.length-1; i>=0; i--) {
// Convert array index to "1000", "1000000", etc
var size = Math.pow(10,(i+1)*3);
// If the number is bigger or equal do the abbreviation
if(size <= number) {
// Here, we multiply by decPlaces, round, and then divide by decPlaces.
// This gives us Nice rounding to a particular decimal place.
number = Math.round(number*decPlaces/size)/decPlaces;
// Handle special case where we round up to the next abbreviation
if((number == 1000) && (i < abbrev.length - 1)) {
number = 1;
i++;
}
// Add the letter for the abbreviation
number += abbrev[i];
// We are done... stop
break;
}
}
return number;
}
出力:
abbrNum(12 , 1) => 12
abbrNum(0 , 2) => 0
abbrNum(1234 , 0) => 1k
abbrNum(34567 , 2) => 34.57k
abbrNum(918395 , 1) => 918.4k
abbrNum(2134124 , 2) => 2.13m
abbrNum(47475782130 , 2) => 47.48b
var pow = Math.pow, floor = Math.floor, abs = Math.abs, log = Math.log;
var abbrev = 'kmb'; // could be an array of strings: [' m', ' Mo', ' Md']
function round(n, precision) {
var prec = Math.pow(10, precision);
return Math.round(n*prec)/prec;
}
function format(n) {
var base = floor(log(abs(n))/log(1000));
var suffix = abbrev[Math.min(2, base - 1)];
base = abbrev.indexOf(suffix) + 1;
return suffix ? round(n/pow(1000,base),2)+suffix : ''+n;
}
デモ:
> tests = [-1001, -1, 0, 1, 2.5, 999, 1234,
1234.5, 1000001, Math.pow(10,9), Math.pow(10,12)]
> tests.forEach(function(x){ console.log(x,format(x)) })
-1001 "-1k"
-1 "-1"
0 "0"
1 "1"
2.5 "2.5"
999 "999"
1234 "1.23k"
1234.5 "1.23k"
1000001 "1m"
1000000000 "1b"
1000000000000 "1000b"