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JavaScript-キーによってオブジェクトの配列を減らす

次のようなオブジェクトの配列の操作：

const arr = [
  {name: "qewregf dqewafs", value: "qewregf dqewafs answer", count: 2},
  {name: "survey with select", value: "survey with select answer", count: 2},
  {name: "werasd", value: "Donald", count: 1},
  {name: "werasd", value: "Jim", count: 1}
];

nameキーの一致する値の配列を減らして、次のような目的の出力を達成しようとしています。

desiredOutput = [
  {name: "qewregf dqewafs", data: [{value: "qewregf dqewafs answer", count: 2}]},
  {name: "survey with select", data: [{value: "survey with select answer", count: 2}]},
  {name: "werasd", data: [{value: "Donald", count: 1}, {value: "Jim", count: 1}]}
]

この試みは配列を減らしますが、上書きせずにネストされた値をマージする方法がありません。

const arr = [{"name":"qewregf dqewafs","value":"qewregf dqewafs answer","count":2},{"name":"survey with select","value":"survey with select answer","count":2},{"name":"werasd","value":"Donald","count":1},{"name":"werasd","value":"Jim","count":1}];

const result = arr.reduce((acc, d) => {
  const found = acc.find(a => a.name === d.name);
  const value = { name: d.name, val: d.value };
  if (found) {
    acc.Push(...value);
  }
  else {
    acc.Push({ name: d.name, data: [{ value: d.value }, { count: d.count }] });
  }
  return acc;
}, []);

console.log(result);

何が欠けていますか？

javascriptarraysjavascript-objects
4
proph3t

あなたのコードは少し目標に近いです、ただ何かを調整する必要があります。

以下のデモのコメントをご覧ください：

  1. いつ acc.findは何も検出せず、1つの要素をプッシュします{name:d.name, data: [value]}

  2. 見つかった場合は、1つをプッシュ{value: ...}データプロパティに。

const arr = [
  {name: "qewregf dqewafs", value: "qewregf dqewafs answer", count: 2},
  {name: "survey with select", value: "survey with select answer", count: 2},
  {name: "werasd", value: "Donald", count: 1},
  {name: "werasd", value: "Jim", count: 1}
];

const result = arr.reduce((acc, d) => {
  const found = acc.find(a => a.name === d.name);
  //const value = { name: d.name, val: d.value };
  const value = { value: d.value, count: d.count }; // the element in data property
  if (!found) {
    //acc.Push(...value);
    acc.Push({name:d.name, data: [value]}) // not found, so need to add data property
  }
  else {
    //acc.Push({ name: d.name, data: [{ value: d.value }, { count: d.count }] });
    found.data.Push(value) // if found, that means data property exists, so just Push new element to found.data.
  }
  return acc;
}, []);

console.log(result)
7
Sphinx

名前をキーとしてマップを作成し、_Object destructing_およびObject.values()を使用して目的の結果を得るだけです。

_const arr = [
  {name: "qewregf dqewafs", value: "qewregf dqewafs answer", count: 2},
  {name: "survey with select", value: "survey with select answer", count: 2},
  {name: "werasd", value: "Donald", count: 1},
  {name: "werasd", value: "Jim", count: 1}
];

let result = Object.values(arr.reduce((a,{name, ...props})=>{
  if(!a[name])
     a[name]  = Object.assign({}, {name,data : [props]});
   else
    a[name].data.Push(props);
  return a;
},{}));

console.log(result);_
0
amrender singh

存在しないかどうかを確認し、新しいオブジェクトを結果セットにプッシュすることで、見つかったオブジェクトの使用を簡略化できます。

次に、valueおよびcountを使用してオブジェクトをdataにプッシュします。

const
    array = [{ name: "qewregf dqewafs", value: "qewregf dqewafs answer", count: 2 }, { name: "survey with select", value: "survey with select answer", count: 2 }, { name: "werasd", value: "Donald", count: 1 }, { name: "werasd", value: "Jim", count: 1 }],
    result = array.reduce((r, { name, value, count }) => {
        var temp = r.find(o => name === o.name);
        if (!temp) {
            r.Push(temp = { name, data: [] });
        }
        temp.data.Push({ value, count });
        return r;
    }, []);

console.log(result);
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0
Nina Scholz

あなたはこのようなことをする必要があります：

const arr = [
  {name: "qewregf dqewafs", value: "qewregf dqewafs answer", count: 2},
  {name: "survey with select", value: "survey with select answer", count: 2},
  {name: "werasd", value: "Donald", count: 1},
  {name: "werasd", value: "Jim", count: 1}
];

const result = arr.reduce((acc, d) => {
  let idx = acc.findIndex(a => a.name === d.name);
  let val = { value: d.value, count: d.count };

  if (idx > -1) {
    acc[idx].data.Push(val);
  } else {
    acc.Push({ name: d.name, data: [val] });
  }

  return acc;
}, []);

console.log(result);

最初にインデックスを見つけてから、その行にデータをプッシュする必要があります。あなたはそれを見つけているだけで、新しい値を配列にプッシュしています。

0
WakeskaterX

あなたは遠くないです。これは、それを実現するためにコードの2行を単純に変更するだけです。

const arr = [
  {name: "qewregf dqewafs", value: "qewregf dqewafs answer", count: 2},
  {name: "survey with select", value: "survey with select answer", count: 2},
  {name: "werasd", value: "Donald", count: 1},
  {name: "werasd", value: "Jim", count: 1}
];

const result = arr.reduce((acc, d) => {
  const found = acc.find(a => a.name === d.name);
  const value = { name: d.name, val: d.value };
  if (found) {
    found.data.Push(value);
  }
  else {
    acc.Push({ name: d.name, data: [{ value: d.value, count: d.count }] });
  }
  return acc;
}, []);

console.log(result)

違いは次のとおりです。

-     acc.Push(...value);
+     found.data.Push(value);


-    acc.Push({ name: d.name, data: [{ value: d.value }, { count: d.count }] });
+    acc.Push({ name: d.name, data: [{ value: d.value, count: d.count }] });
0
Scott Sauyet