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mysqlテーブルの行を列に転置する方法

現在のmysqlテーブルは次のようになります。

PunchID EmpID   PunchEvent  PunchDateTime
1       0456    clockin     5/14/2013 8:36:26 AM
48      0456    breakout    5/14/2013 12:01:29 PM
53      0456    breakin     5/14/2013 12:28:31 PM
54      0456    clockout    5/14/2013 2:28:33 PM
57      0456    clockin     5/15/2013 7:38:34 AM
58      0456    breakout    5/15/2013 7:38:39 AM
59      0456    breakin     5/15/2013 7:38:41 AM
60      0456    clockout    5/15/2013 7:38:42 AM

次のように、曜日に基づいてグループ化された結果セットを返します。

Day       ClockIn      BreakOut    BreakIn      ClockOut
Tuesday   8:36:26 AM  12:01:29 PM  12:28:31 PM  2:28:33 PM
Wednesday 7:38:34 AM  etc, etc...

これは私の現在のクエリです。ただし、毎日の最初のパンチのみを返します。

SELECT DATE_FORMAT(PunchDateTime, '%W') as day, PunchEvent, DATE_FORMAT(PunchDateTime, '%l:%m:%s %p') as time FROM timeclock_punchlog WHERE EmpID = '0456' GROUP BY DATE(PunchDateTime) ORDER BY PunchDateTime ASC;

誰かがこれで私を助けることができますか？マイクに感謝

mysqlsqlpivot
16
dmikester1
SELECT  DATE_FORMAT(PunchDateTime, '%W') DAY,
        MAX(CASE WHEN PunchEvent = 'ClockIn' THEN DATE_FORMAT(PunchDateTime, '%r') END) ClockIn,
        MAX(CASE WHEN PunchEvent = 'BreakOut' THEN DATE_FORMAT(PunchDateTime, '%r') END) BreakOut,
        MAX(CASE WHEN PunchEvent = 'BreakIn' THEN DATE_FORMAT(PunchDateTime, '%r') END) BreakIn,
        MAX(CASE WHEN PunchEvent = 'ClockOut' THEN DATE_FORMAT(PunchDateTime, '%r') END) ClockOut
FROM    tableName
WHERE   EmpID = 456
GROUP   BY DATE_FORMAT(PunchDateTime, '%W')
ORDER   BY PunchDateTime

出力

╔═══════════╦═════════════╦═════════════╦═════════════╦═════════════╗
║    DAY    ║   CLOCKIN   ║  BREAKOUT   ║   BREAKIN   ║  CLOCKOUT   ║
╠═══════════╬═════════════╬═════════════╬═════════════╬═════════════╣
║ Tuesday   ║ 08:36:26 AM ║ 12:01:29 PM ║ 12:28:31 PM ║ 02:28:33 PM ║
║ Wednesday ║ 07:38:34 AM ║ 07:38:39 AM ║ 07:38:41 AM ║ 07:38:42 AM ║
╚═══════════╩═════════════╩═════════════╩═════════════╩═════════════╝
37
John Woo