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すべてのPKおよびFKの取得

各テーブルからすべての主キーと外部キーを抽出する必要がある大きなデータベースがあります。

PgAdmin IIIを使用しています。

これを自動的に行い、各テーブルを手動で行わない方法はありますか?

20
Nick Ginanto

次のようなクエリで関数 pg_get_constraintdef(constraint_oid) を使用できます。

SELECT conrelid::regclass AS table_from
     , conname
     , pg_get_constraintdef(oid)
FROM   pg_constraint
WHERE  contype IN ('f', 'p ')
AND    connamespace = 'public'::regnamespace  -- your schema here
ORDER  BY conrelid::regclass::text, contype DESC;

結果:

 table_from | conname    | pg_get_constraintdef
------------+------------+----------------------
 tbl        | tbl_pkey   | PRIMARY KEY (tbl_id)
 tbl        | tbl_col_fk | FOREIGN KEY (col) REFERENCES tbl2(col) ON UPDATE CASCADE
...

指定されたスキーマ内のすべてのテーブルのすべての主キーと外部キーを、PKを最初にtablenameで並べ替えて返します。

に関するマニュアル)pg_constraint

オブジェクト識別子のタイプregclassregnamespace、...)に関するマニュアル。

31

Erwinソリューションに基づく:

SELECT conrelid::regclass AS "FK_Table"
      ,CASE WHEN pg_get_constraintdef(c.oid) LIKE 'FOREIGN KEY %' THEN substring(pg_get_constraintdef(c.oid), 14, position(')' in pg_get_constraintdef(c.oid))-14) END AS "FK_Column"
      ,CASE WHEN pg_get_constraintdef(c.oid) LIKE 'FOREIGN KEY %' THEN substring(pg_get_constraintdef(c.oid), position(' REFERENCES ' in pg_get_constraintdef(c.oid))+12, position('(' in substring(pg_get_constraintdef(c.oid), 14))-position(' REFERENCES ' in pg_get_constraintdef(c.oid))+1) END AS "PK_Table"
      ,CASE WHEN pg_get_constraintdef(c.oid) LIKE 'FOREIGN KEY %' THEN substring(pg_get_constraintdef(c.oid), position('(' in substring(pg_get_constraintdef(c.oid), 14))+14, position(')' in substring(pg_get_constraintdef(c.oid), position('(' in substring(pg_get_constraintdef(c.oid), 14))+14))-1) END AS "PK_Column"
FROM   pg_constraint c
JOIN   pg_namespace n ON n.oid = c.connamespace
WHERE  contype IN ('f', 'p ')
AND pg_get_constraintdef(c.oid) LIKE 'FOREIGN KEY %'
ORDER  BY pg_get_constraintdef(c.oid), conrelid::regclass::text, contype DESC;

フォームのテーブルを返します:

| FK_Table | FK_Column | PK_Table | PK_Column |
9
profimedica

pg_get_constraintdef()を解析する必要はありません。pg_constraint取得するテーブルその他の詳細the docs )。

ここに constraint_typeは次のいずれかです。

  • p-主キー
  • f-外部キー
  • u-ユニーク
  • c-チェック制約
  • x-exclusion
  • ...

アーウィンの答え に基づく:

SELECT c.conname                                 AS constraint_name,
   c.contype                                     AS constraint_type,
   sch.nspname                                   AS "self_schema",
   tbl.relname                                   AS "self_table",
   ARRAY_AGG(col.attname ORDER BY u.attposition) AS "self_columns",
   f_sch.nspname                                 AS "foreign_schema",
   f_tbl.relname                                 AS "foreign_table",
   ARRAY_AGG(f_col.attname ORDER BY f_u.attposition) AS "foreign_columns",
   pg_get_constraintdef(c.oid)                   AS definition
FROM pg_constraint c
       LEFT JOIN LATERAL UNNEST(c.conkey) WITH ORDINALITY AS u(attnum, attposition) ON TRUE
       LEFT JOIN LATERAL UNNEST(c.confkey) WITH ORDINALITY AS f_u(attnum, attposition) ON f_u.attposition = u.attposition
       JOIN pg_class tbl ON tbl.oid = c.conrelid
       JOIN pg_namespace sch ON sch.oid = tbl.relnamespace
       LEFT JOIN pg_attribute col ON (col.attrelid = tbl.oid AND col.attnum = u.attnum)
       LEFT JOIN pg_class f_tbl ON f_tbl.oid = c.confrelid
       LEFT JOIN pg_namespace f_sch ON f_sch.oid = f_tbl.relnamespace
       LEFT JOIN pg_attribute f_col ON (f_col.attrelid = f_tbl.oid AND f_col.attnum = f_u.attnum)
GROUP BY constraint_name, constraint_type, "self_schema", "self_table", definition, "foreign_schema", "foreign_table"
ORDER BY "self_schema", "self_table";

結果はschematableの順に並べられます。

テクニカルノート:参照 この質問 についてwith ordinality

5
Evgeny Nozdrev

最近、これを、infoスキーマに基づいてCRUDユーティリティを構築するデータアクセスレイヤーに実装する必要がありましたが、最終的にはこれでうまくいきました。

SELECT

    current_schema() AS "schema",
    current_catalog AS "database",
    "pg_constraint".conrelid::regclass::text AS "primary_table_name",
    "pg_constraint".confrelid::regclass::text AS "foreign_table_name",

    (
        string_to_array(
            (
                string_to_array(
                    pg_get_constraintdef("pg_constraint".oid),
                    '('
                )
            )[2],
            ')'
        )
    )[1] AS "foreign_column_name",

    "pg_constraint".conindid::regclass::text AS "constraint_name",

    TRIM((
        string_to_array(
            pg_get_constraintdef("pg_constraint".oid),
            '('
        )
    )[1]) AS "constraint_type",

    pg_get_constraintdef("pg_constraint".oid) AS "constraint_definition"

FROM pg_constraint AS "pg_constraint"

JOIN pg_namespace AS "pg_namespace" ON "pg_namespace".oid = "pg_constraint".connamespace

WHERE

    "pg_constraint".contype IN ( 'f', 'p' )
    AND
    "pg_namespace".nspname = current_schema()
    AND
    "pg_constraint".conrelid::regclass::text IN ('whatever_table_name')
1
hajikelist