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1つのクエリの最初と最後のレコード

そのようなデータから最初と最後のスコアを選択したい

WITH t AS (
SELECT 1 user_id, '2019-05-15'::date AS created_at, 4 as score
UNION ALL
SELECT 1 user_id, '2019-05-13'::date AS created_at, 12 as score
UNION ALL
SELECT 2 user_id, '2019-05-15'::date AS created_at, 7 as score
UNION ALL
SELECT 3 user_id, '2019-05-13'::date AS created_at, 6 as score
),
first_score AS (
    SELECT DISTINCT ON (user_id)
        created_at, score, user_id
    FROM t
    ORDER BY user_id, created_at ASC
),
last_score AS (
    SELECT DISTINCT ON (user_id)
        created_at, score, user_id
    FROM t
    ORDER BY user_id, created_at DESC
)

select
    md5(u.user_id::varchar) user_id,
    u.created_at signup_date,
    fhs.created_at first_score_created_at,
    fhs.score first_score,
    lhs.created_at last_score_created_at,
    lhs.score last_score
from t as u 
    INNER JOIN first_score fhs ON fhs.user_id = u.user_id
    INNER JOIN last_score lhs ON lhs.user_id = u.user_id;

私の質問：1つのクエリでfirst_scoreとlast_scoreを結合する1つのサブクエリを作成する方法はありますか？

postgresqlorder-bydistinct
1
Bear Brown
WITH t AS (
SELECT 1 user_id, '2019-05-15'::date AS created_at, 4 as score
UNION ALL
SELECT 1 user_id, '2019-05-13'::date AS created_at, 12 as score
UNION ALL
SELECT 2 user_id, '2019-05-15'::date AS created_at, 7 as score
UNION ALL
SELECT 3 user_id, '2019-05-13'::date AS created_at, 6 as score
)
SELECT
    md5(user_id::varchar) user_id,
    created_at signup_date,
    MIN(created_at) OVER (PARTITION BY user_id) first_score_created_at,
    FIRST_VALUE(score) OVER (PARTITION BY user_id ORDER BY created_at ASC) first_score,
    MAX(created_at) OVER (PARTITION BY user_id) last_score_created_at,
    FIRST_VALUE(score) OVER (PARTITION BY user_id ORDER BY created_at DESC) last_score
FROM t
2
Akina