Pythonを使用してHTMLコンテンツを電子メールで送信する方法を教えてください。簡単なテキストを送ることができます。
から Python v2.7.14 documentation - 18.1.11。email:Examples :
これは、代替テキスト形式のHTMLメッセージを作成する方法の例です。
#! /usr/bin/python
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "[email protected]"
you = "[email protected]"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
# sendmail function takes 3 arguments: sender's address, recipient's address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()
あなたは私の メーラー モジュールを使ってみるかもしれません。
from mailer import Mailer
from mailer import Message
message = Message(From="[email protected]",
To="[email protected]")
message.Subject = "An HTML Email"
message.Html = """<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""
sender = Mailer('smtp.example.com')
sender.send(message)
これが、受け入れられた答えの Gmail 実装です。
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "[email protected]"
you = "[email protected]"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
mail = smtplib.SMTP('smtp.gmail.com', 587)
mail.ehlo()
mail.starttls()
mail.login('userName', 'password')
mail.sendmail(me, you, msg.as_string())
mail.quit()
これは、Content-Typeヘッダーを 'text/html'と指定するだけで、HTML Eメールを送信する簡単な方法です。
import email.message
import smtplib
msg = email.message.Message()
msg['Subject'] = 'foo'
msg['From'] = '[email protected]'
msg['To'] = '[email protected]'
msg.add_header('Content-Type','text/html')
msg.set_payload('Body of <b>message</b>')
# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
s.starttls()
s.login(email_login,
email_passwd)
s.sendmail(msg['From'], [msg['To']], msg.as_string())
s.quit()
これがサンプルコードです。これは Python Cookbook サイトにあるコードからヒントを得たものです(正確なリンクは見つかりません)
def createhtmlmail (html, text, subject, fromEmail):
"""Create a mime-message that will render HTML in popular
MUAs, text in better ones"""
import MimeWriter
import mimetools
import cStringIO
out = cStringIO.StringIO() # output buffer for our message
htmlin = cStringIO.StringIO(html)
txtin = cStringIO.StringIO(text)
writer = MimeWriter.MimeWriter(out)
#
# set up some basic headers... we put subject here
# because smtplib.sendmail expects it to be in the
# message body
#
writer.addheader("From", fromEmail)
writer.addheader("Subject", subject)
writer.addheader("MIME-Version", "1.0")
#
# start the multipart section of the message
# multipart/alternative seems to work better
# on some MUAs than multipart/mixed
#
writer.startmultipartbody("alternative")
writer.flushheaders()
#
# the plain text section
#
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
pout = subpart.startbody("text/plain", [("charset", 'us-ascii')])
mimetools.encode(txtin, pout, 'quoted-printable')
txtin.close()
#
# start the html subpart of the message
#
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
#
# returns us a file-ish object we can write to
#
pout = subpart.startbody("text/html", [("charset", 'us-ascii')])
mimetools.encode(htmlin, pout, 'quoted-printable')
htmlin.close()
#
# Now that we're done, close our writer and
# return the message body
#
writer.lastpart()
msg = out.getvalue()
out.close()
print msg
return msg
if __name__=="__main__":
import smtplib
html = 'html version'
text = 'TEST VERSION'
subject = "BACKUP REPORT"
message = createhtmlmail(html, text, subject, 'From Host <[email protected]>')
server = smtplib.SMTP("smtp_server_address","smtp_port")
server.login('username', 'password')
server.sendmail('[email protected]', '[email protected]', message)
server.quit()
実際、 yagmail は少し異なるアプローチを取りました。
デフォルトでは、HTMLを送信するでしょう。それはもう17世紀ではありません。
もちろん、それをオーバーライドすることができますが、ここに行きます:
import yagmail
yag = yagmail.SMTP("[email protected]", "mypassword")
html_msg = """<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""
yag.send("[email protected]", "the subject", html_msg)
インストール方法やその他のすばらしい機能については、 github をご覧ください。
これは、CCおよびBCCオプションとともにsmtplib
を使用して、PythonからプレーンテキストおよびHTMLのEメールを送信するための実用的な例です。
https://varunver.wordpress.com/2017/01/26/python-smtplib-send-plaintext-and-html-emails/
#!/usr/bin/env python
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
def send_mail(params, type_):
email_subject = params['email_subject']
email_from = "[email protected]"
email_to = params['email_to']
email_cc = params.get('email_cc')
email_bcc = params.get('email_bcc')
email_body = params['email_body']
msg = MIMEMultipart('alternative')
msg['To'] = email_to
msg['CC'] = email_cc
msg['Subject'] = email_subject
mt_html = MIMEText(email_body, type_)
msg.attach(mt_html)
server = smtplib.SMTP('YOUR_MAIL_SERVER.DOMAIN.COM')
server.set_debuglevel(1)
toaddrs = [email_to] + [email_cc] + [email_bcc]
server.sendmail(email_from, toaddrs, msg.as_string())
server.quit()
# Calling the mailer functions
params = {
'email_to': '[email protected]',
'email_cc': '[email protected]',
'email_bcc': '[email protected]',
'email_subject': 'Test message from python library',
'email_body': '<h1>Hello World</h1>'
}
for t in ['plain', 'html']:
send_mail(params, t)
Office 365の組織のアカウントからメールを送信するための最も簡単な方法:
from O365 import Message
html_template = """
<html>
<head>
<title></title>
</head>
<body>
{}
</body>
</html>
"""
final_html_data = html_template.format(df.to_html(index=False))
o365_auth = ('sender_username@company_email.com','Password')
m = Message(auth=o365_auth)
m.setRecipients('receiver_username@company_email.com')
m.setSubject('Weekly report')
m.setBodyHTML(final)
m.sendMessage()
ここでdfはhtml Tableに変換されたhtml Tableに変換されたデータフレームです。
これがboto3を使ったAWSの私の答えです。
subject = "Hello"
html = "<b>Hello Consumer</b>"
client = boto3.client('ses', region_name='us-east-1', aws_access_key_id="your_key",
aws_secret_access_key="your_secret")
client.send_email(
Source='ACME <[email protected]>',
Destination={'ToAddresses': [email]},
Message={
'Subject': {'Data': subject},
'Body': {
'Html': {'Data': html}
}
}