1024x768の解像度のウィンドウがあります。クリックまたはマウスオーバーしたときに、x、yの値を見つけたいと思います。どうやってやるの?
import sys
from PyQt4 import QtGui, QtCore
class Example(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.initUI()
def initUI(self):
qbtn = QtGui.QPushButton('Quit', self)
#qbtn.clicked.connect(QtCore.QCoreApplication.instance().quit)
qbtn.clicked.connect(self.test)
qbtn.resize(qbtn.sizeHint())
qbtn.move(50, 50)
self.setGeometry(0, 0, 1024, 768)
self.setWindowTitle('Quit button')
self.setWindowFlags(self.windowFlags() | QtCore.Qt.FramelessWindowHint)
self.show()
def test(self):
print "show the position of mouse cursor in screen resolution: x is ?? , y is ??"
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
import sys
from PyQt4 import QtGui, QtCore
class Example(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.initUI()
def mousePressEvent(self, QMouseEvent):
print QMouseEvent.pos()
def mouseReleaseEvent(self, QMouseEvent):
cursor =QtGui.QCursor()
print cursor.pos()
def initUI(self):
qbtn = QtGui.QPushButton('Quit', self)
qbtn.resize(qbtn.sizeHint())
qbtn.move(50, 50)
self.setGeometry(0, 0, 1024, 768)
self.setWindowTitle('Quit button')
self.setWindowFlags(self.windowFlags() | QtCore.Qt.FramelessWindowHint)
self.show()
def test(self):
print "test"
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
出力:
PyQt4.QtCore.QPoint(242, 285)
PyQt4.QtCore.QPoint(1741, 423)
PyQt4.QtCore.QPoint(439, 372)
(x、y)座標を取得する別の方法:
def mouseReleaseEvent(self, QMouseEvent):
print('(', QMouseEvent.x(), ', ', QMouseEvent.y(), ')')