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「lt;」を置き換えますおよび「gt;」 SQLサーバーで「<」および「>」を使用

こんにちは私はxmlの初心者です

このようなクエリがあります

SELECT  ProjectId, 
       ProjectCode, 
       ProjectName, 
       TechId, 
      -- LocationId, 

      ( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
       t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
    FROM GeographicLocation t2
    WHERE GeoId = t1.LocationId
    FOR XML  PATH('Location') ),
       RtoId, 
       CreatedBy,
       CreatedOn,
       LastUpdatedBy,
       LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')

xmlを返します

<ProjectInfo>
<ProjectId>1</ProjectId>
<ProjectCode>US-W1-00001</ProjectCode>
<ProjectName>Rees</ProjectName>
<TechId>1</TechId>
&lt;Location&gt;&lt;GeoId&gt;235&lt;/GeoId&gt;&lt;PoliticalDivisionId&gt;2&lt;/PoliticalDivisionId&gt;&lt;GeographicLocationName&gt;UNITED STATES&lt;/GeographicLocationName&gt;&lt;IsoCode&gt;US&lt;/IsoCode&gt;&lt;/Location&gt;
<RtoId>3</RtoId>
<CreatedBy>1</CreatedBy>
<CreatedOn>2013-06-30T20:55:21.587</CreatedOn>
<LastUpdatedBy>1</LastUpdatedBy>
<LastUpdatedOn>2013-06-30T20:55:21.587</LastUpdatedOn>

prjectタグは、<および>の形式で表示されます。しかし、Locationの内部タグは「<」および「>」として表示されます。それらを<および>に置き換えるにはどうすればよいですか

更新：質問に小さなエラーがありました。インナーxmlはrtoid用ではなく、Location用でした

クエリを更新しました

SELECT  ProjectId, 
       ProjectCode, 
       ProjectName, 
       TechId, 
      -- LocationId, 

      replace(replace( ( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
       t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
    FROM GeographicLocation t2
    WHERE GeoId = t1.LocationId
    FOR XML  PATH('Location') ), '&lt;', '<'), '&gt;', '>'),
       RtoId, 
       CreatedBy,
       CreatedOn,
       LastUpdatedBy,
       LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')

それでも同じ

sql-serverfor-xmlfor-xml-path
11
Kuntady Nithesh

正しい方法は TYPEディレクティブ を使用していると思います

SELECT  ProjectId, 
        ...,
      ( SELECT Geo, ...
        FROM GeographicLocation t2
        WHERE GeoId = t1.LocationId
        FOR XML  PATH('Location'), TYPE),
       RtoId,                      ^^^^
       ...
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
13
Savva Sergey

私が見つけた方法は、明示的に置き換えることです：

select ProjectId, ProjectCode, ProjectName, TechId,
       replace(replace(RtoId, '&lt;', '<'), '&gt;', '>') as RtoId, 
       . . .
from (<your query here>)
10
Gordon Linoff
    SELECT  ProjectId, 
       ProjectCode, 
       ProjectName, 
       TechId, 
      -- LocationId, 
      replace(replace(( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
       t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
    FROM GeographicLocation t2
    WHERE GeoId = t1.LocationId
    FOR XML  PATH('Location') ), '&lt;', '<'), '&gt;', '>')
       RtoId, 
       CreatedBy,
       CreatedOn,
       LastUpdatedBy,
       LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
3
Hiren Dhaduk

データをxmlにフォーマットするには、cast（@xml as xml）を使用します。

2
user2384628
SELECT ProjectId,
       ProjectCode, 
       ProjectName, 
       TechId, 
      -- LocationId, 
      cast(( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
       t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
    FROM GeographicLocation t2
    WHERE GeoId = t1.LocationId
    FOR XML  PATH('Location') ) as xml),
       RtoId, 
       CreatedBy,
       CreatedOn,
       LastUpdatedBy,
       LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
1
Nikls

してみてください：

(SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,
        Longitude,Latitude,ParentLocationId,
        t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
    FROM GeographicLocation t2
    WHERE GeoId = t1.LocationId
        FOR XML  PATH('Location'), type
        ).value('(./text())[1]','varchar(max)')
1
TechDo