データベースに2つのテーブルがあります。
表1
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| name | family | phone | email | gender | phone2 | address | birthdate |
-------------------------------------------------------------------------
テーブル#2
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| gender | address | phone | birthdate |
-----------------------------------------
表#1の列addressおよびphone2は空で、列genderおよびbirthdateの値は表#2と同じです。
テーブル#2からデータを読み取り、テーブル#1のaddressおよびphone2をテーブル#2の値で更新するにはどうすればよいですかaddressおよびphonegenderおよびbirthdateの場合の列は各行で同じですか?
例:これは表#1の一部のデータです
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| name | family | phone | email | gender | phone2 | address | birthdate |
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| john | doe | 12345| [email protected]| Male | | | 1980-01-01|
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| mike | clark | 65432| [email protected]| Male | | | 1990-01-01|
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| Sara | King | 875465| [email protected]|Female| | | 1970-01-01|
-------------------------------------------------------------------------
そして、ここにテーブル#2のいくつかのデータがあります
-----------------------------------------
| gender | address | phone | birthdate |
-----------------------------------------
| Male | 1704test|0457852|1980-01-01 |
-----------------------------------------
| Female | 1705abcs|0986532|1970-01-01 |
-----------------------------------------
| Male | 1602cyzd|0326589|1990-01-01 |
-----------------------------------------
テーブル#1をテーブル#2のデータで更新し、genderおよびbirthdateを確認して、テーブル#1を次のようにします
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| name | family | phone | email | gender | phone2 | address | birthdate |
-------------------------------------------------------------------------
| john | doe | 12345| [email protected]| Male |0457852 |1704test | 1980-01-01|
-------------------------------------------------------------------------
| mike | clark | 65432| [email protected]| Male |0326589 |1602cyzd| 1990-01-01|
-------------------------------------------------------------------------
| Sara | King | 875465| [email protected]|Female |0986532 |1705abcs| 1970-01-01|
-------------------------------------------------------------------------
これどうやってするの?
希望する結果を得るには、いくつかの方法があります。
不確定な方法
(テーブル2の多くの行がテーブル1の1つと一致する場合)
UPDATE T1
SET address = T2.address,
phone2 = T2.phone
FROM #Table1 T1
JOIN #Table2 T2
ON T1.gender = T2.gender
AND T1.birthdate = T2.birthdate
または、もう少し簡潔な形式
UPDATE #Table1
SET address = #Table2.address,
phone2 = #Table2.phone
FROM #Table2
WHERE #Table2.gender = #Table1.gender
AND #Table2.birthdate = #Table1.birthdate
またはCTEで
WITH CTE
AS (SELECT T1.address AS tgt_address,
T1.phone2 AS tgt_phone,
T2.address AS source_address,
T2.phone AS source_phone
FROM #Table1 T1
INNER JOIN #Table2 T2
ON T1.gender = T2.gender
AND T1.birthdate = T2.birthdate)
UPDATE CTE
SET tgt_address = source_address,
tgt_phone = source_phone
決定論的方法
MERGE
は、非決定的な結果を受け入れるのではなく、エラーをスローします
MERGE #Table1 T1
USING #Table2 T2
ON T1.gender = T2.gender
AND T1.birthdate = T2.birthdate
WHEN MATCHED THEN
UPDATE SET address = T2.address,
phone2 = T2.phone;
または、複数の一致がある場合、特定のレコードを選択できます
APPLY
UPDATE T1
SET address = T2.address,
phone2 = T2.phone
FROM #Table1 T1
CROSS APPLY (SELECT TOP 1 *
FROM #Table2 T2
WHERE T1.gender = T2.gender
AND T1.birthdate = T2.birthdate
ORDER BY T2.PrimaryKey) T2
..またはCTE
WITH T2
AS (SELECT *,
ROW_NUMBER() OVER (PARTITION BY gender, birthdate ORDER BY primarykey) AS RN
FROM #Table2)
UPDATE T1
SET address = T2.address,
phone2 = T2.phone
FROM #Table1 T1
JOIN T2
ON T1.gender = T2.gender
AND T1.birthdate = T2.birthdate
AND T2.RN = 1;
UPDATE TS
SET TS.TaskFullAddress = L.FullAddress
FROM [dbo].[TaskOrders] TS
INNER JOIN Locations L
ON TS.ClientId = L.ClientId;