4つの列を含むテーブルがあり、5番目の列には、前の4つからnull以外の列がいくつあるかを格納します。次に例を示します。
Xは任意の値です。
Column1 | Column2 | Column3 | Column4 | Count
X | X | NULL | X | 3
NULL | NULL | X | X | 2
NULL | NULL | NULL | NULL | 0
select
T.Column1,
T.Column2,
T.Column3,
T.Column4,
(
select count(*)
from (values (T.Column1), (T.Column2), (T.Column3), (T.Column4)) as v(col)
where v.col is not null
) as Column5
from Table1 as T
SELECT Column1,
Column2,
Column3,
Column4,
CASE WHEN Column1 IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN Column2 IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN Column3 IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN Column4 IS NOT NULL THEN 1 ELSE 0 END AS Column5
FROM Table
SELECT Column1, Column2, Column3, Column4,
Column5 = LEN(COALESCE(LEFT(Column1,1),''))
+ LEN(COALESCE(LEFT(Column2,1),''))
+ LEN(COALESCE(LEFT(Column3,1),''))
+ LEN(COALESCE(LEFT(Column4,1),''))
FROM dbo.YourTable;
デモ:
DECLARE @x TABLE(a VARCHAR(32),b INT,c VARCHAR(32),d VARCHAR(32));
INSERT @x VALUES
('01',3023,NULL,'blat'),
('02',NULL, NULL,'blat'),
('03',5,NULL,'blat'),
('04',24,'bo','blat'),
(NULL, NULL, NULL, NULL);
SELECT a, b, c, d,
LEN(COALESCE(LEFT(a,1),''))
+ LEN(COALESCE(LEFT(b,1),''))
+ LEN(COALESCE(LEFT(c,1),''))
+ LEN(COALESCE(LEFT(d,1),''))
FROM @x;