2つの日付間の営業時間を計算する
2つの日付間の営業時間を計算するにはどうすればよいですか？たとえば、2つの日付があります。 2010年1月1日15:00と2010年4月1日12:00そして、平日の09:00から17:00までの勤務時間があります。SQLで勤務時間を計算するにはどうすればよいですか。
SQL 2005向けに修正および修正されたBaranの回答
SQL 2008以降：
-- =============================================
-- Author: Baran Kaynak (modified by Kodak 2012-04-18)
-- Create date: 14.03.2011
-- Description: 09:30 ile 17:30 arasındaki iş saatlerini hafta sonlarını almayarak toplar.
-- =============================================
CREATE FUNCTION [dbo].[WorkTime]
(
@StartDate DATETIME,
@FinishDate DATETIME
)
RETURNS BIGINT
AS
BEGIN
DECLARE @Temp BIGINT
SET @Temp=0
DECLARE @FirstDay DATE
SET @FirstDay = CONVERT(DATE, @StartDate, 112)
DECLARE @LastDay DATE
SET @LastDay = CONVERT(DATE, @FinishDate, 112)
DECLARE @StartTime TIME
SET @StartTime = CONVERT(TIME, @StartDate)
DECLARE @FinishTime TIME
SET @FinishTime = CONVERT(TIME, @FinishDate)
DECLARE @WorkStart TIME
SET @WorkStart = '09:00'
DECLARE @WorkFinish TIME
SET @WorkFinish = '17:00'
DECLARE @DailyWorkTime BIGINT
SET @DailyWorkTime = DATEDIFF(MINUTE, @WorkStart, @WorkFinish)
IF (@StartTime<@WorkStart)
BEGIN
SET @StartTime = @WorkStart
END
IF (@FinishTime>@WorkFinish)
BEGIN
SET @FinishTime=@WorkFinish
END
IF (@FinishTime<@WorkStart)
BEGIN
SET @FinishTime=@WorkStart
END
IF (@StartTime>@WorkFinish)
BEGIN
SET @StartTime = @WorkFinish
END
DECLARE @CurrentDate DATE
SET @CurrentDate = @FirstDay
DECLARE @LastDate DATE
SET @LastDate = @LastDay
WHILE(@CurrentDate<=@LastDate)
BEGIN
IF (DATEPART(dw, @CurrentDate)!=1 AND DATEPART(dw, @CurrentDate)!=7)
BEGIN
IF (@CurrentDate!=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = @Temp + @DailyWorkTime
END
--IF it starts at startdate and it finishes not this date find diff between work finish and start as minutes
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @StartTime, @WorkFinish)
END
ELSE IF (@CurrentDate!=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @WorkStart, @FinishTime)
END
--IF it starts and finishes in the same date
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = DATEDIFF(MINUTE, @StartTime, @FinishTime)
END
END
SET @CurrentDate = DATEADD(day, 1, @CurrentDate)
END
-- Return the result of the function
IF @Temp<0
BEGIN
SET @Temp=0
END
RETURN @Temp
END
SQL 2005以前：
-- =============================================
-- Author: Baran Kaynak (modified by Kodak 2012-04-18)
-- Create date: 14.03.2011
-- Description: 09:30 ile 17:30 arasındaki iş saatlerini hafta sonlarını almayarak toplar.
-- =============================================
CREATE FUNCTION [dbo].[WorkTime]
(
@StartDate DATETIME,
@FinishDate DATETIME
)
RETURNS BIGINT
AS
BEGIN
DECLARE @Temp BIGINT
SET @Temp=0
DECLARE @FirstDay DATETIME
SET @FirstDay = DATEADD(dd, 0, DATEDIFF(dd, 0, @StartDate))
DECLARE @LastDay DATETIME
SET @LastDay = DATEADD(dd, 0, DATEDIFF(dd, 0, @FinishDate))
DECLARE @StartTime DATETIME
SET @StartTime = @StartDate - DATEADD(dd, DATEDIFF(dd, 0, @StartDate), 0)
DECLARE @FinishTime DATETIME
SET @FinishTime = @FinishDate - DATEADD(dd, DATEDIFF(dd, 0, @FinishDate), 0)
DECLARE @WorkStart DATETIME
SET @WorkStart = CONVERT(DATETIME, '09:00', 8)
DECLARE @WorkFinish DATETIME
SET @WorkFinish = CONVERT(DATETIME, '17:00', 8)
DECLARE @DailyWorkTime BIGINT
SET @DailyWorkTime = DATEDIFF(MINUTE, @WorkStart, @WorkFinish)
IF (@StartTime<@WorkStart)
BEGIN
SET @StartTime = @WorkStart
END
IF (@FinishTime>@WorkFinish)
BEGIN
SET @FinishTime=@WorkFinish
END
IF (@FinishTime<@WorkStart)
BEGIN
SET @FinishTime=@WorkStart
END
IF (@StartTime>@WorkFinish)
BEGIN
SET @StartTime = @WorkFinish
END
DECLARE @CurrentDate DATETIME
SET @CurrentDate = @FirstDay
DECLARE @LastDate DATETIME
SET @LastDate = @LastDay
WHILE(@CurrentDate<=@LastDate)
BEGIN
IF (DATEPART(dw, @CurrentDate)!=1 AND DATEPART(dw, @CurrentDate)!=7)
BEGIN
IF (@CurrentDate!=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = @Temp + @DailyWorkTime
END
--IF it starts at startdate and it finishes not this date find diff between work finish and start as minutes
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @StartTime, @WorkFinish)
END
ELSE IF (@CurrentDate!=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @WorkStart, @FinishTime)
END
--IF it starts and finishes in the same date
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = DATEDIFF(MINUTE, @StartTime, @FinishTime)
END
END
SET @CurrentDate = DATEADD(day, 1, @CurrentDate)
END
-- Return the result of the function
IF @Temp<0
BEGIN
SET @Temp=0
END
RETURN @Temp
END
私はこれが非常に古い投稿であることを知っていますが、ここに2つのイベント間の営業時間/分を計算するために最近書いた関数があります。また、表で定義する必要がある休日も考慮します。
この関数は、間隔を分単位で返します。必要に応じて、60で割って時間を取得できます。
これはSQL Server 2008でテストされています。誰かの役に立つことを願っています。
Create Function GetWorkingMin(@StartDate DateTime, @EndDate DateTime, @Country Varchar(2)) Returns Int
AS
Begin
Declare @WorkMin int = 0 -- Initialize counter
Declare @Reverse bit -- Flag to hold if direction is reverse
Declare @StartHour int = 9 -- Start of business hours (can be supplied as an argument if needed)
Declare @EndHour int = 17 -- End of business hours (can be supplied as an argument if needed)
Declare @Holidays Table (HDate DateTime) -- Table variable to hold holidayes
-- If dates are in reverse order, switch them and set flag
If @StartDate>@EndDate
Begin
Declare @TempDate DateTime=@StartDate
Set @StartDate=@EndDate
Set @EndDate=@TempDate
Set @Reverse=1
End
Else Set @Reverse = 0
-- Get country holidays from table based on the country code (Feel free to remove this or modify as per your DB schema)
Insert Into @Holidays (HDate) Select HDate from HOLIDAY Where COUNTRYCODE=@Country and HDATE>=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)
If DatePart(HH, @StartDate)<@StartHour Set @StartDate = DateAdd(hour, @StartHour, DateDiff(DAY, 0, @StartDate)) -- If Start time is less than start hour, set it to start hour
If DatePart(HH, @StartDate)>=@EndHour+1 Set @StartDate = DateAdd(hour, @StartHour+24, DateDiff(DAY, 0, @StartDate)) -- If Start time is after end hour, set it to start hour of next day
If DatePart(HH, @EndDate)>=@EndHour+1 Set @EndDate = DateAdd(hour, @EndHour, DateDiff(DAY, 0, @EndDate)) -- If End time is after end hour, set it to end hour
If DatePart(HH, @EndDate)<@StartHour Set @EndDate = DateAdd(hour, @EndHour-24, DateDiff(DAY, 0, @EndDate)) -- If End time is before start hour, set it to end hour of previous day
If @StartDate>@EndDate Return 0
-- If Start and End is on same day
If DateDiff(Day,@StartDate,@EndDate) <= 0
Begin
If Datepart(dw,@StartDate)>1 And DATEPART(dw,@StartDate)<7 -- If day is between sunday and saturday
If (Select Count(*) From @Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)) = 0 -- If day is not a holiday
If @EndDate<@StartDate Return 0 Else Set @WorkMin=DATEDIFF(MI, @StartDate, @EndDate) -- Calculate difference
Else Return 0
Else Return 0
End
Else Begin
Declare @Partial int=1 -- Set partial day flag
While DateDiff(Day,@StartDate,@EndDate) > 0 -- While start and end days are different
Begin
If Datepart(dw,@StartDate)>1 And DATEPART(dw,@StartDate)<7 -- If this is a weekday
Begin
If (Select Count(*) From @Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)) = 0 -- If this is not a holiday
Begin
If @Partial=1 -- If this is the first iteration, calculate partial time
Begin
Set @WorkMin=@WorkMin + DATEDIFF(MI, @StartDate, DateAdd(hour, @EndHour, DateDiff(DAY, 0, @StartDate)))
Set @StartDate=DateAdd(hour, @StartHour+24, DateDiff(DAY, 0, @StartDate))
Set @Partial=0
End
Else Begin -- If this is a full day, add full minutes
Set @WorkMin=@WorkMin + (@EndHour-@StartHour)*60
Set @StartDate = DATEADD(DD,1,@StartDate)
End
End
Else Set @StartDate = DATEADD(DD,1,@StartDate)
End
Else Set @StartDate = DATEADD(DD,1,@StartDate)
End
If Datepart(dw,@StartDate)>1 And DATEPART(dw,@StartDate)<7 -- If last day is a weekday
If (Select Count(*) From @Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)) = 0 -- And it is not a holiday
If @Partial=0 Set @WorkMin=@WorkMin + DATEDIFF(MI, @StartDate, @EndDate) Else Set @WorkMin=@WorkMin + DATEDIFF(MI, DateAdd(hour, @StartHour, DateDiff(DAY, 0, @StartDate)), @EndDate)
End
If @Reverse=1 Set @WorkMin=-@WorkMin
Return @WorkMin
End
以下のスクリプトに示すように、最初のステップは就業日を計算することです。
DECLARE @TotalWorkDays INT, @TotalTimeDiff DECIMAL(18, 2), @DateFrom DATETIME, @DateTo DATETIME;
SET @DateFrom = '2017-06-05 11:19:11.287';
SET @DateTo = '2017-06-07 09:53:14.750';
SET @TotalWorkDays = DATEDIFF(DAY, @DateFrom, @DateTo)
-(DATEDIFF(WEEK, @DateFrom, @DateTo) * 2)
-CASE
WHEN DATENAME(WEEKDAY, @DateFrom) = 'Sunday'
THEN 1
ELSE 0
END+CASE
WHEN DATENAME(WEEKDAY, @DateTo) = 'Saturday'
THEN 1
ELSE 0
END;
2番目の手順では、2つの日付の秒単位の差を取得し、この差を360360で割って時間に変換します（次のスクリプトを参照）。
SET @TotalTimeDiff =
(
SELECT DATEDIFF(SECOND,
(
SELECT CONVERT(TIME, @DateFrom)
),
(
SELECT CONVERT(TIME, @DateTo)
)) / 3600.0
);
最後の部分では、上記の最初のステップの出力に24（1日の合計時間数）を掛けてから、2番目のステップの出力に追加します。
SELECT(@TotalWorkDays * 24.00) + @TotalTimeDiff;
最後に、労働時間を計算するためのユーザー定義関数を作成するために使用できる完全なスクリプトを以下に示します。
CREATE FUNCTION [dbo].[fn_GetTotalWorkingHours]
(
@DateFrom Datetime,
@DateTo Datetime
)
RETURNS DECIMAL(18,2)
AS
BEGIN
DECLARE @TotalWorkDays INT, @TotalTimeDiff DECIMAL(18, 2)
SET @TotalWorkDays = DATEDIFF(DAY, @DateFrom, @DateTo)
-(DATEDIFF(WEEK, @DateFrom, @DateTo) * 2)
-CASE
WHEN DATENAME(WEEKDAY, @DateFrom) = 'Sunday'
THEN 1
ELSE 0
END+CASE
WHEN DATENAME(WEEKDAY, @DateTo) = 'Saturday'
THEN 1
ELSE 0
END;
SET @TotalTimeDiff =
(
SELECT DATEDIFF(SECOND,
(
SELECT CONVERT(TIME, @DateFrom)
),
(
SELECT CONVERT(TIME, @DateTo)
)) / 3600.0
);
RETURN (SELECT(@TotalWorkDays * 24.00) + @TotalTimeDiff)
END
GO
完全な方法については、この記事で説明します。 https://www.sqlshack.com/how-to-calculate-work-days-and-hours-in-sql-server/
DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
DECLARE @WORKINGHOURS INT
DECLARE @Days INT
SET @StartDate = '2010/01/01'
SET @EndDate = '2010/04/01'
--number of working days
SELECT @Days =
(DATEDIFF(dd, @StartDate, @EndDate) + 1)
-(DATEDIFF(wk, @StartDate, @EndDate) * 2)
-(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
--8 hours a day
SET @WORKINGHOURS = @Days * 8
SELECT @WORKINGHOURS
@Pavanredの代替ソリューション、よりデータベースの角度から物事に来ます：
検討するすべての日付を含むテーブルを作成します。毎日、次のように労働時間数を設定します。
WorkingDate Hours Comment
=========== ===== ==================
1 Jan 2011 0 Saturday
2 Jan 2011 0 Sunday
3 Jan 2011 0 Public Holiday
4 Jan 2011 8 Normal working day
5 Jan 2011 8 Normal working day
-- and so on, for all the days you want to report on.
これにはわずかな設定が必要になります。週末に対して自動的に数週間事前に設定し、必要に応じて祝日などに合わせて調整できます。
ただし、セットアップで失うものは、クエリの容易さで得られます。
SELECT
SUM(Hours)
FROM
working_days
WHERE
WorkingDate BETWEEN @StartDate AND @EndDate
...これは、就業日を定義するためにより複雑なルールを追加する必要がある場合、または就業時間が日によって異なる場合など、より簡単なアプローチとして機能します.
また、実際のコードを変更して営業日の定義を変更したり、祝日を追加したりする必要がないため、ルールをより簡単に「編集可能」にします。
-- =============================================
-- Author: Baran Kaynak
-- Create date: 14.03.2011
-- Description: 09:30 ile 17:30 arasındaki iş saatlerini hafta sonlarını almayarak toplar.
-- =============================================
CREATE FUNCTION [dbo].[WorkTime]
(
@StartDate DATETIME,
@FinishDate DATETIME
)
RETURNS BIGINT
AS
BEGIN
DECLARE @Temp BIGINT
SET @Temp=0
DECLARE @FirstDay DATE
SET @FirstDay = CONVERT(DATE, @StartDate, 112)
DECLARE @LastDay DATE
SET @LastDay = CONVERT(DATE, @FinishDate, 112)
DECLARE @StartTime TIME
SET @StartTime = CONVERT(TIME, @StartDate)
DECLARE @FinishTime TIME
SET @FinishTime = CONVERT(TIME, @FinishDate)
DECLARE @WorkStart TIME
SET @WorkStart = '09:30'
DECLARE @WorkFinish TIME
SET @WorkFinish = '17:30'
IF (@StartTime<@WorkStart)
BEGIN
SET @StartTime = @WorkStart
END
IF (@FinishTime>@WorkFinish)
BEGIN
SET @FinishTime=@WorkFinish
END
DECLARE @CurrentDate DATE
SET @CurrentDate = CONVERT(DATE, @StartDate, 112)
DECLARE @LastDate DATE
SET @LastDate = CONVERT(DATE, @FinishDate, 112)
WHILE(@CurrentDate<=@LastDate)
BEGIN
IF (DATEPART(dw, @CurrentDate)!=1 AND DATEPART(dw, @CurrentDate)!=7)
BEGIN
IF (@CurrentDate!=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = (@Temp + (9*60))
END
--IF it starts at startdate and it finishes not this date find diff between work finish and start as minutes
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @StartTime, @WorkFinish)
END
ELSE IF (@CurrentDate!=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @WorkStart, @FinishTime)
END
--IF it starts and finishes in the same date
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = DATEDIFF(MINUTE, @StartDate, @FinishDate)
END
END
SET @CurrentDate = DATEADD(day, 1, @CurrentDate)
END
-- Return the result of the function
IF @Temp<0
BEGIN
SET @Temp=0
END
RETURN @Temp
END
GO
ALTER FUNCTION WorkTime_fn (@StartDate DATETIME, @FinishDate DATETIME)
RETURNS VARCHAR(9)
AS
BEGIN
DECLARE @Temp BIGINT
SET @Temp=0
DECLARE @FirstDay VARCHAR(9)
SET @FirstDay = CONVERT(VARCHAR(9),@StartDate, 112)
DECLARE @LastDay VARCHAR(9)
SET @LastDay = CONVERT(VARCHAR(9),@FinishDate, 112)
DECLARE @StartTime VARCHAR(9)
SET @StartTime = CONVERT(VARCHAR(9),@StartDate, 108)
DECLARE @FinishTime VARCHAR(9)
SET @FinishTime = CONVERT(VARCHAR(9),@FinishDate, 108)
DECLARE @WorkStart VARCHAR(9)
SET @WorkStart = '09:30:00'
DECLARE @WorkFinish VARCHAR(9)
SET @WorkFinish = '17:30:00'
IF (@StartTime<@WorkStart)
BEGIN
SET @StartTime = @WorkStart
END
IF (@FinishTime>@WorkFinish)
BEGIN
SET @FinishTime=@WorkFinish
END
DECLARE @CurrentDate VARCHAR(9)
SET @CurrentDate = CONVERT(VARCHAR(9),@StartDate, 112)
DECLARE @LastDate VARCHAR(9)
SET @LastDate = CONVERT(VARCHAR(9),@FinishDate, 112)
WHILE(@CurrentDate<=@LastDate)
BEGIN
IF (DATEPART(dw, @CurrentDate)!=1 AND DATEPART(dw, @CurrentDate)!=7)
BEGIN
IF (@CurrentDate!=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = (@Temp + (8*60))
END
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate!=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @StartTime, @WorkFinish)
END
ELSE IF (@CurrentDate!=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = @Temp + DATEDIFF(MINUTE, @WorkStart, @FinishTime)
END
ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate=@LastDay)
BEGIN
SET @Temp = DATEDIFF(MINUTE, @StartTime, @FinishTime)
END
END
SET @CurrentDate = CONVERT(VARCHAR(9),DATEADD(day, 1, @CurrentDate),112)
END
Return @TEMP
END
質問では、祝日を考慮すべきではないため、この答えはそれだけです-週末を考慮して営業時間を計算しますが、祝日を無視します。
また、指定された開始日時と終了日時は営業時間内であると想定しています
この前提では、コードは営業日の開始時刻または終了時刻を考慮せず、1日あたりの合計営業時間数のみを考慮します。あなたの例では、09：00から17:00の間に8営業時間があります。整数である必要はありません。以下の式は1分の精度で計算していますが、1秒または他の精度にするのは簡単です。
祝日を考慮に入れる必要がある場合は、祝日をリストする別のテーブルが必要になります。このテーブルは年ごと、州ごと、国ごとに異なる場合があります。メイン式は同じままである場合がありますが、指定された日付範囲内にある祝日の結果時間から減算する必要があります。
式
SELECT
DATEDIFF(minute, StartDT, EndDT) / 60.0
- DATEDIFF(day, StartDT, EndDT) * 16
- DATEDIFF(week, StartDT, EndDT) * 16 AS BusinessHours
FROM T
それがどのように機能するかを理解するために、さまざまなケースをカバーするいくつかのサンプルデータでテーブルを作成しましょう：
DECLARE @T TABLE (StartDT datetime2(0), EndDT datetime2(0));
INSERT INTO @T VALUES
('2012-03-05 09:00:00', '2012-03-05 15:00:00'), -- simple part of the same day
('2012-03-05 10:00:00', '2012-03-06 10:00:00'), -- full day across the midnight
('2012-03-05 11:00:00', '2012-03-06 10:00:00'), -- less than a day across the midnight
('2012-03-05 10:00:00', '2012-03-06 15:00:00'), -- more than a day across the midnight
('2012-03-09 16:00:00', '2012-03-12 10:00:00'), -- over the weekend, less than 7 days
('2012-03-06 16:00:00', '2012-03-15 10:00:00'), -- over the weekend, more than 7 days
('2012-03-09 16:00:00', '2012-03-19 10:00:00'); -- over two weekends
クエリ
SELECT
StartDT,
EndDT,
DATEDIFF(minute, StartDT, EndDT) / 60.0
- DATEDIFF(day, StartDT, EndDT) * 16
- DATEDIFF(week, StartDT, EndDT) * 16 AS BusinessHours
FROM @T;
次の結果が生成されます。
+---------------------+---------------------+---------------+
| StartDT | EndDT | BusinessHours |
+---------------------+---------------------+---------------+
| 2012-03-05 09:00:00 | 2012-03-05 15:00:00 | 6.000000 |
| 2012-03-05 10:00:00 | 2012-03-06 10:00:00 | 8.000000 |
| 2012-03-05 11:00:00 | 2012-03-06 10:00:00 | 7.000000 |
| 2012-03-05 10:00:00 | 2012-03-06 15:00:00 | 13.000000 |
| 2012-03-09 16:00:00 | 2012-03-12 10:00:00 | 2.000000 |
| 2012-03-06 16:00:00 | 2012-03-15 10:00:00 | 50.000000 |
| 2012-03-09 16:00:00 | 2012-03-19 10:00:00 | 42.000000 |
+---------------------+---------------------+---------------+
SQL Serverでは DATEDIFF が指定されたdatepart境界と指定されたstartdateおよびenddate。
毎日8営業時間です。 2つの日付間の合計時間数を計算し、真夜中の数に1日あたり16の非営業時間を掛けた値を引き、次に週末の数に16を掛けた値（土曜日と日曜日の8 + 8営業時間）を引きます。
2015-03-16 09：52：24.000のようなインラインバージョンStart/EndDateTimeは次のとおりです。07:00:00のようなStart/EndTime（営業時間）これはかさばりますが、selectステートメントで機能します
Functionバージョンでも投稿します。
Case when <StartDate>= <EndDate> then 0
When Convert(date,<StartDate>) = Convert(date,<EndDate>) Then
IIF( DATEPART(Dw,<StartDate>) in(1,7)
or Convert(time,<StartDate>) > Convert(time,<EndTime>)
or Convert(time,<EndDate>) < Convert(time,<StartTime>),0,
DateDiff(S,IIF(Convert(time,<StartDate>) < Convert(time,<StartTime>),Convert(time,<StartTime>),Convert(time,<StartDate>))
,IIF(Convert(time,<EndDate>) > Convert(time,<EndTime>), Convert(time,<EndTime>), Convert(time,<EndDate>))))
when Convert(date,<StartDate>) <> Convert(date,<EndDate>) then
IIF(DATEPART(Dw,<StartDate>) in(1,7) or Convert(time,<StartDate>) > Convert(time,<EndTime>),0 ,DateDiff(S,IIF(Convert(time,<StartDate>) < Convert(time,<StartTime>),Convert(time,<StartTime>),Convert(time,<StartDate>)), Convert(time,<EndTime>)))
+ IIF(DATEPART(Dw,<EndDate>) in(1,7) or Convert(time,<EndDate>) < Convert(time,<StartTime>),0,DateDiff(S,Convert(time,<StartTime>),IIF(Convert(time,<EndDate>) > Convert(time,<EndTime>), Convert(time,<EndTime>), Convert(time,<EndDate>))))
else -333
end --as pday
+IIF(DatePart(wEEk,<StartDate>) = DatePart(wEEk,<EndDate>)
,0, (DateDiff(wk,dateadd(d,-datepart(dw,<StartDate>),dateadd(ww,1,<StartDate>)),DATEADD(wk, DATEDIFF(wk, 6, <EndDate>), 6)-1) * 5)) * Datediff(S, Convert(time,<StartTime>),Convert(time,<EndTime>)) --Fullweek_days
+Case When Convert(date,<StartDate>) = Convert(date,<EndDate>) then 0
When DatePart(wEEk,<StartDate>) <> DatePart(wEEk,<EndDate>) then
IIF( datepart(dw,<StartDate>) = 7,0,DateDIFF(DAY,<StartDate>+1,dateadd(d,-datepart(dw,<StartDate>),dateadd(ww,1,<StartDate>)))) -- beginFulldays
+IIF( datepart(dw,<EndDate>) = 1,0,DateDIFF(DAY,DATEADD(wk, DATEDIFF(wk, 6, <EndDate>), 6),<EndDate> -1)) --Endfulldays
When DatePart(wEEk,<StartDate>) = DatePart(wEEk,<EndDate>) then
DateDiff(DAY,<StartDate>+1,<EndDate> )
ELSE -333 END * Datediff(S, Convert(time,<StartTime>),Convert(time,<EndTime>))
機能バージョンは次のとおりです。
CREATE FUNCTION [dbo].[rsf_BusinessTime]
(
@startDateTime Datetime,
@endDateTime Datetime ,
@StartTime VarChar(12),
@EndTime VarChar(12) )
RETURNS BIGINT
As
BEGIN
Declare @totalSeconds BigInt,
@SecondsInDay int,
@dayStart Time = Convert(time,@StartTime),
@dayEnd Time =Convert(time,@EndTime),
@SatAfterStart Datetime = dateadd(d,-datepart(dw,@startDateTime),dateadd(ww,1,@startDateTime)),
@Sunbeforend Datetime = DATEADD(wk, DATEDIFF(wk, 6, @endDateTime), 6)
-- This function calculates the seconds between the start and end dates provided for business hours.
-- It only returns the time between the @start and @end time (hour of day) of the work week.
-- Weekend days are removed.
-- Holidays are not considered.
Set @SecondsInDay = Datediff(S, @dayStart,@dayEnd)
Set @totalSeconds =
--first/last/sameday
Case when @startDateTime= @endDateTime then 0
When Convert(date,@startDateTime) = Convert(date,@endDateTime) Then
IIF( DATEPART(Dw,@startDateTime) in(1,7)
or Convert(time,@startDateTime) > @dayEnd
or Convert(time,@endDateTime) < @dayStart,0,
DateDiff(S,IIF(Convert(time,@startDateTime) < @dayStart,@dayStart,Convert(time,@startDateTime))
,IIF(Convert(time,@endDateTime) > @dayEnd, @dayEnd, Convert(time,@endDateTime))))
when Convert(date,@startDateTime) <> Convert(date,@endDateTime) then
IIF(DATEPART(Dw,@startDateTime) in(1,7) or Convert(time,@startDateTime) > @dayEnd,0 ,DateDiff(S,IIF(Convert(time,@startDateTime) < @dayStart,@dayStart,Convert(time,@startDateTime)), @dayEnd))
+ IIF(DATEPART(Dw,@endDateTime) in(1,7) or Convert(time,@endDateTime) < @dayStart,0,DateDiff(S,@dayStart,IIF(Convert(time,@endDateTime) > @dayEnd, @dayEnd, Convert(time,@endDateTime))))
else -333
end --as pday
+IIF(DatePart(wEEk,@startDateTime) = DatePart(wEEk,@endDateTime)
,0, (DateDiff(wk,@SatAfterStart,@Sunbeforend-1) * 5)) * @SecondsInDay --Fullweek_days
+Case When Convert(date,@startDateTime) = Convert(date,@endDateTime) then 0
When DatePart(wEEk,@startDateTime) <> DatePart(wEEk,@endDateTime) then
IIF( datepart(dw,@startDateTime) = 7,0,DateDIFF(DAY,@startDateTime+1,@SatAfterStart)) -- beginFulldays
+IIF( datepart(dw,@endDateTime) = 1,0,DateDIFF(DAY,@Sunbeforend,@endDateTime -1)) --Endfulldays
When DatePart(wEEk,@startDateTime) = DatePart(wEEk,@endDateTime) then
DateDiff(DAY,@startDateTime+1,@endDateTime )
ELSE -333 END * @SecondsInDay
Return @totalSeconds
END
このソリューションについてどう思いますか？
「While」ループを使用しません。
create function dbo.WorkingHoursBetweenDates ( @StartDate datetime, @EndDate datetime, @StartTime time, @EndTime time )
returns decimal ( 10, 2 )
as
begin
return
case
when @EndTime < @StartTime or @EndDate < @StartDate then
0
else
round
( ( dbo.WorkingDaysBetweenDates(@StartDate, @EndDate) -
( dbo.WorkingDaysBetweenDates(@StartDate, @StartDate) *
case
when cast ( @StartDate as time ) > @EndTime then
1
else
datediff
( mi,
@StartTime
, case
when @StartTime > cast ( @StartDate as time ) then
@StartTime
else
cast ( @StartDate as time )
end
) /
( datediff ( mi, @StartTime, @EndTime ) + 0.0 )
end
) -
( dbo.WorkingDaysBetweenDates(@EndDate, @EndDate) *
case
when cast ( @EndDate as time ) < @StartTime then
1
else
datediff
( mi,
case
when @EndTime < cast ( @EndDate as time ) then
@EndTime
else
cast ( @EndDate as time )
end,
@EndTime
) /
( datediff ( mi, @StartTime, @EndTime ) + 0.0 )
end
)
) *
( datediff ( mi, @StartTime, @EndTime ) / 60.0 ), 2
)
end
end
------
create function dbo.WorkingDaysBetweenDates ( @StartDate date, @EndDate date )
returns int
as
begin
return
( datediff(dd, @StartDate, @EndDate) + 1 ) -
( datediff(wk, @StartDate, @EndDate) * 2 ) -
( case when datename(dw, @StartDate) = 'Sunday' then 1 else 0 end ) -
( case when datename(dw, @EndDate) = 'Saturday' then 1 else 0 end ) -
( select
count ( 1 )
from
dbo.Tb_Holidays
where
HDate between @StartDate and @EndDate
and datename(dw, HDate) not in ( 'Sunday', 'Saturday' )
)
end
関数を使用しない代替ソリューションを次に示します。これは、 numbers table の存在に依存していることに注意してください。少なくとも、追跡しているタスクにかかる最大日数が入力されています。
これは祝日を考慮しません。週末に仕事をしていない場合は、@ OpeningHoursテーブル変数で開始時刻と終了時刻を午前0時に設定するとうまくいきます。
これを8500行の「実世界」データに対してテストし、パフォーマンスが高いことがわかりました。
DECLARE @OpeningHours TABLE ([DayOfWeek] INTEGER, OpeningTime TIME(0), ClosingTime TIME(0));
INSERT
@OpeningHours ([DayOfWeek], OpeningTime, ClosingTime)
VALUES
(1, '10:00', '16:00') -- Sun
, (2, '06:30', '23:00') -- Mon
, (3, '06:30', '23:00') -- Tue
, (4, '06:30', '23:00') -- Wed
, (5, '06:30', '23:00') -- Thu
, (6, '06:30', '23:00') -- Fri
, (7, '08:00', '20:00'); -- Sat
DECLARE @Tasks TABLE ([Description] VARCHAR(50), CreatedDateTime DATETIME, CompletedDateTime DATETIME);
INSERT
@Tasks ([Description], CreatedDateTime, CompletedDateTime)
VALUES
('Make tea', '20170404 10:00', '20170404 10:12')
, ('Make coffee', '20170404 23:35', '20170405 06:32')
, ('Write complex SQL query', '20170406 00:00', '20170406 23:32')
, ('Rewrite complex SQL query', '20170406 23:50', '20170410 10:50');
SELECT
WorkingMinutesToRespond =
SUM(CASE WHEN CAST(Tasks.CreatedDateTime AS DATE) = CAST(Tasks.CompletedDateTime AS DATE) THEN
CASE WHEN CAST(Tasks.CreatedDateTime AS TIME) < OpeningHours.OpeningTime THEN
-- Task created before opening time
DATEDIFF(MINUTE, OpeningHours.OpeningTime, CAST(Tasks.CompletedDateTime AS TIME))
ELSE
DATEDIFF(MINUTE, Tasks.CreatedDateTime, Tasks.CompletedDateTime)
END
ELSE
CASE WHEN Tasks.CoveredDate = CAST(Tasks.CreatedDateTime AS DATE) THEN
-- This is the day the task was created
CASE WHEN CAST(Tasks.CreatedDateTime AS TIME(0)) > OpeningHours.ClosingTime THEN
0 -- after working hours
ELSE
-- during or before working hours
CASE WHEN CAST(Tasks.CreatedDateTime AS TIME(0)) < OpeningHours.OpeningTime THEN
-- before opening time; take the whole day into account
DATEDIFF(MINUTE, OpeningHours.OpeningTime, OpeningHours.ClosingTime)
ELSE
-- during opening hours; take part of the day into account
DATEDIFF(MINUTE, CAST(Tasks.CreatedDateTime AS TIME), OpeningHours.ClosingTime)
END
END
ELSE
-- This is the day the task was completed
CASE WHEN Tasks.CoveredDate = CAST(Tasks.CompletedDateTime AS DATE) THEN
CASE WHEN CAST(Tasks.CompletedDateTime AS TIME(0)) < OpeningHours.OpeningTime THEN
0 -- before working hours (unlikely to occur)
ELSE
-- during or after working hours
CASE WHEN CAST(Tasks.CompletedDateTime AS TIME(0)) > OpeningHours.ClosingTime THEN
-- after closing time (also unlikely); take the whole day into account
DATEDIFF(MINUTE, OpeningHours.OpeningTime, OpeningHours.ClosingTime)
ELSE
-- during opening hours; take part of the day into account
DATEDIFF(MINUTE, OpeningHours.OpeningTime, CAST(Tasks.CompletedDateTime AS TIME(0)))
END
END
ELSE
DATEDIFF(MINUTE, OpeningHours.OpeningTime, OpeningHours.ClosingTime)
END
END
END)
, Tasks.Description
, Tasks.CreatedDateTime
, Tasks.CompletedDateTime
FROM
(
SELECT
Tasks.Description
, Tasks.CreatedDateTime
, Tasks.CompletedDateTime
, CoveredDate = CAST(DATEADD(DAY, Numbers.Number, Tasks.CreatedDateTime) AS DATE)
FROM
@Tasks Tasks
INNER JOIN (SELECT * FROM Numbers WHERE Number >= 0) Numbers ON DATEDIFF(DAY, Tasks.CreatedDateTime, Tasks.CompletedDateTime) >= Numbers.Number
) Tasks
INNER JOIN @OpeningHours OpeningHours ON DATEPART(WEEKDAY, Tasks.CoveredDate) = OpeningHours.[DayOfWeek]
GROUP BY
Tasks.Description
, Tasks.CreatedDateTime
, Tasks.CompletedDateTime
ORDER BY
Tasks.CompletedDateTime;
別の考え方、週の最初の日が月曜日の場合、以下の関数は正しく動作します
create function fn_worktime(@Datetime1 DateTime,@Datetime2 DateTime)
Returns BigInt
as
Begin
Declare
@Date1 Date,
@Date2 Date,
@DateIndex Date,
@minutes int,
@lastDayMinutes int,
@StartTime int , --in minutes
@FinishTime int ,--in minutes
@WorkDayLong int --in minutes
Set @StartTime =8 * 60 + 30 -- 8:30
Set @FinishTime =17* 60 + 30 -- 17:30
Set @WorkDayLong =@FinishTime - @StartTime
Set @Date1 = Convert(Date,@DateTime1)
Set @Date2 = Convert(Date,@DateTime2)
Set @minutes=DateDiff(minute,@DateTime1,DateAdd(MINUTE,@FinishTime ,convert(DateTime,@Date1)))
if @minutes<0 OR DatePart(dw,@Date1) in (6,7) -- you can even check holdays here. '(6 Saturday,7 Sunday) according to SET DATEFIRST 1'
Set @minutes=0
Set @DateIndex=DateAdd(day,1,@Date1)
While @DateIndex<@Date2
Begin
if DatePart(dw,@DateIndex) not in (6,7) -- you can even check holdays here. '(6 Saturday,7 Sunday) according to SET DATEFIRST 1'
set @minutes=@minutes+@WorkDayLong
Set @DateIndex=DateAdd(day,1,@DateIndex)
End
if DatePart(dw,@DateIndex) not in (6,7) -- you can even check holdays here
Begin
set @lastDayMinutes=DateDiff(minute,DateAdd(MINUTE ,@StartTime ,convert(DateTime,@Date2)),@DateTime2)
if @lastDayMinutes>@WorkDayLong
set @lastDayMinutes=@WorkDayLong
if @Date1<>@Date2
set @minutes=@minutes+@lastDayMinutes
Else
Set @minutes=@minutes+@lastDayMinutes-@WorkDayLong
End
return @minutes
End
私は実際にこれを以前に行いましたが、営業時間のすべての変数（週末、休日など）を考慮することは非常に困難です、このタスクはSQLの外で行うのが最適だと思います